Question

What mass of ammonium nitrate should be heated to produce 8.96 litres of steam?

[Note : Relative molecular mass of $N{H}_{4}N{O}_3$ is 80]

• A. $32g$
• B. $16g$
• C. $80g$
• D. $22.4g$

Answer 1

Answer: (B)

$16g$

$N{H}_{4}N{O}_3⟶N_{2}O+2H_{2}O$
1 mol 1 mol 2 mol
80 gm 22.4 lit 2$\times$22.4 lit

Now,

$44.8lit$ steam is produced by $80$gm of $N{H}_{4}N{O}_3$

$\therefore$ Mass of $N{H}_{4}N{O}_3$ required to produce $8.96$ lit steam = $\frac{80}{44.8}$ $\times$ $8.96$ = $16gm$