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Addition Reaction

What mass of ...

Question

What mass of $C O_{2}$ could be formed by the reaction of $16 g C H_{4}$ with $48 g o f O_{2}$ ?
$C H_{4} + 2 O_{2} ⟶ C O_{2} + 2 H_{2} O$

44 g

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33 g

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16 g

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24 g

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Solution

The correct option is C 33 g
$C H_{4} + 2 O_{2} ⟶ C O_{2} + 2 H_{2} O$
$1 m o l 2 m o l$
$16 g 64 g$
given, 16 g ; $48 g = 1.5 m o l$
Thus, $O_{2}$ is the limiting reactant
$∴ 2 m o l O_{2} g i v e = 44 g C O_{2}$
$1.5 m o l O_{2} g i v e = \frac{44}{5} \times 1.5 = 33 g C O_{2}$

Suggest Corrections

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