Question

What mass of hydrogen peroxide will be present in 2 litres of a 5 molar solution? Calculate the mass of oxygen which will be liberated by decomposition of 200 ml of this solution.

Answer 1

$Molarity=\frac{Wt}{Mwt\times Volume}$

$5=\frac{Wt}{34\times 2}$

$Wt=340gram$

$H_2{O}_2⟶H_{2}O+\frac{1}{2}{O}_2$

$1$ mole of $H_2{O}_2$ will give $\frac{1}{2}$ mole of $O_2$.

So the gain volume of $O_2$ is $100ml$,

mass of $O_2$ is-

$\frac{Wt}{Mwt}=\frac{Volume}{22.4}$

$Wt=\frac{32\times 100}{22400}=\frac{1}{7}gram$