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Question

What mass of $$Na$$ will contain $$6.023 \times  10^{23}$$ number of atoms?


A
23 g
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B
46 g
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C
6.023 g
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D
11.5 g
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Solution

The correct option is A $$23$$ g
One mole of each substance contains $$N_A = 6.023\times10^{23}$$ atoms. Here $$N_A$$ = Avogadro number.
Mass of one mole of atoms = Molar mass
So, the mass of one mole of $$Na$$ = $$23$$ g = $$6.023 \times  10^{23}$$ number of atoms. (Atomic mass of $$Na$$ = $$23$$ u and molar mass is numerically equal to the atomic mass)
Hence, option A is correct.

Chemistry

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