What mass of NaCl would be decomposed by 9.8 g of H2SO4 if 120g of NaHSO4 and 27.5g of HCl are produced in a reaction? Assuming the law of conservation of mass.
What mass of NaCl would be decomposed by 9.8 g of H2SO4 if 120g of NaHSO4 and 27.5g of HCl are produced in a reaction? Assuming the law of conservation of mass.
The correct option is A 4.95g
Explanation:
Law of conservation of mass states that mass can neither be
created nor be destroyed but it can only be transformed from one form to
another form.
This also means that total mass on the reactant side must be equal
to the total mass on the product side.
The chemical equation for the reaction of
sodium chloride and sulfuric acid follow:
NaCl+H2SO4→NaHSO4+HCl
Let the mass of sodium chloride be X
grams
We
are given:
Mass of sulfuric acid = 9.8 grams
Mass of sodium bisulfite = 12 grams
Mass of hydrochloric acid = 2.75 grams
Total mass on reactant side = 9.8+x
Total mass on product side = 12+2.75=14.75 g
So,
by applying the law of conservation of mass, we get:
9.8+x=14.75
x=4.95
Hence,
the mass of NaCl that would be decomposed will be x=4.95 grams.
option A is correct.
Explanation:
Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.
This also means that total mass on the reactant side must be equal to the total mass on the product side.
The chemical equation for the reaction of sodium chloride and sulfuric acid follow:
NaCl+H2SO4→NaHSO4+HCl
Let the mass of sodium chloride be X grams
We are given:
Mass of sulfuric acid = 9.8 grams
Mass of sodium bisulfite = 12 grams
Mass of hydrochloric acid = 2.75 grams
Total mass on reactant side = 9.8+x
Total mass on product side = 12+2.75=14.75 g
So, by applying the law of conservation of mass, we get:
9.8+x=14.75
x=4.95
Hence, the mass of NaCl that would be decomposed will be x=4.95 grams.
option A is correct.
