What mass of $N a C l$ would contain the same total number of ions as 245 g of $M g C l_{2}$ ?

245 g

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225 g

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263 g

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None of these

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Solution

The correct option is B 225 g
$(24 + 35.5 \times 2)$ gm of $m g c l_{2} \to 3$ No ion
245 gm of $m g c l_{2} \to \frac{3}{(24 + 70)} \times 245 g m$
$(\frac{3}{24 + 70}) \times 245$ ion of Nacl $\to \frac{(23 + 35.5)}{2 \times N a} \times \frac{3}{(24 + 70)} \times 245 g m$

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\frac{({(245 + 232)}^{2} - {(245 - 232)}^{2})}{(245 + 232)}

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What mass of NaCl would contain the same total number of ions as 245 g of MgCl2?

The correct option is B 225 g(24+35.5×2) gm of mgcl2→3 No ion245 gm of mgcl2→3(24+70)×245gm(324+70)×245 ion of Nacl →(23+35.5)2×Na×3(24+70)×245gm

What mass of $N a C l$ would contain the same total number of ions as 245 g of $M g C l_{2}$ ?

The correct option is B 225 g
$(24 + 35.5 \times 2)$ gm of $m g c l_{2} \to 3$ No ion
245 gm of $m g c l_{2} \to \frac{3}{(24 + 70)} \times 245 g m$
$(\frac{3}{24 + 70}) \times 245$ ion of Nacl $\to \frac{(23 + 35.5)}{2 \times N a} \times \frac{3}{(24 + 70)} \times 245 g m$