What mass of pentane in mg- C5H12- produces 3-01 - 1022 CO2 molecules when burnt is excess oxygen O2-

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Ideal Gas Equation

What mass of ...

Question

What mass of pentane (in mg), $C_{5} H_{12}$ , produces $3.01 \times 10^{22} C O_{2}$ molecules when burnt is excess oxygen $O_{2}$ ?

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Solution

The balancd chemical reaction for the combustion of pentane is as given below.
$C_{5} H_{12} (g) + 8 O_{2} (g) ⟶ 5 C O_{2} (g) + 6 H_{2} O (l)$
$1 m o l 5 m o l$
$5 \times 6.02 \times 10^{23}$ molecules of CO_2 are from $72 g C_{5} H_{12}$

Thus, $3.01 \times 10^{22}$ molecules of $C O_{2}$ are from $\frac{72 \times 3.01 \times 10^{22}}{5 \times 6.02 \times 10^{23}} = 0.72 g C_{5} H_{12}$

Hence, $720$ mg of pentane, $C_{5} H_{12}$ , produces $3.01 \times 10^{22} C O_{2}$ molecules when burnt is excess oxygen $O_{2}$ .

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