wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

What mass of sodium carbonate, Na2CO3 is needed to make 120 mL of a 1.5 M solution? (Given formula weight of sodium carbonate = 106 amu)

A
295 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
9.5 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
19 g
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
589 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
E
19,000,g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 19 g
Number of moles of Na2CO3=120mL1000mL/L×1.5mol/L=0.180mol
The formula weight of Na2CO3=106g/mol
Mass of Na2CO3=106g/mol×0.180mol=19g

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Percentage Composition and Molecular Formula
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon