What mass of sodium carbonate, Na2CO3 is needed to make 120 mL of a 1.5 M solution? (Given formula weight of sodium carbonate = 106 amu)
A
295 g
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B
9.5 g
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C
19 g
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D
589 g
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E
19,000,g
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Solution
The correct option is A 19 g Number of moles of Na2CO3=120mL1000mL/L×1.5mol/L=0.180mol The formula weight of Na2CO3=106g/mol Mass of Na2CO3=106g/mol×0.180mol=19g