Question

What mass of sodium chloride would be decomposed by 9.8 g of sulphuric acid, if 12g of soidum bisulphate and 2.75 g of hydrogen chloride were produced in a reaction, assuming that the law of conservation of mass is true.
${\text{NaCl + H}}_{\text{2}}{\text{SO}}_{\text{4}}\to {\text{NaHSO}}_{\text{4}}\text{+ 2HCl}$

Answer 1

$NaCl+H_{2}S{O}_4⟶NaHS{O}_4+2HCl$

Moles of $H_{2}S{O}_4=\frac{9.5}{98}=0.1$ $moles$

Moles of $NaHS{O}_4=\frac{12}{120}=0.1$ $moles$

$1$ $mole$ of $NaCl$ reacts with $1$ $mole$ $H_{2}S{O}_4$ to give $1$ $mole$ $NaHS{O}_4$.

So, $0.1$ $mole$ of $NaCl$ have reacted

Mass of $NaCl$ reacted $=0.1\times 58=5.85$ $gm$