What mass of zinc is required to produce 0.2 mole of hydrogen gas on reaction with dilute HCl. Atomic mass of zinc is 65.

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Solution

Zn + 2HCl(aq) → ZnCl₂ (aq) + H₂ (g)
1 mole of Zn is required to produce 1 mole of hydrogen gas. Therefore, to produce 0.2 mole of hydrogen gas, 0.2 mole of Zn is required.
Mass of Zn required = 0.2 $\times$ 65 = 13 g.

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What mass of zinc is required to produce 0.2 mole of hydrogen gas on reaction with dilute HCl. Atomic mass of zinc is 65.

Zn + 2HCl(aq) → ZnCl2 (aq) + H2 (g) 1 mole of Zn is required to produce 1 mole of hydrogen gas. Therefore, to produce 0.2 mole of hydrogen gas, 0.2 mole of Zn is required. Mass of Zn required = 0.2×65 = 13 g.

Zn + 2HCl(aq) → ZnCl₂ (aq) + H₂ (g)
1 mole of Zn is required to produce 1 mole of hydrogen gas. Therefore, to produce 0.2 mole of hydrogen gas, 0.2 mole of Zn is required.
Mass of Zn required = 0.2 $\times$ 65 = 13 g.