What measure of angle must be subtracted from $183^{o}$ to make it a supplementary angle of one-third of the given angle?

119^{o}

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64^{o}

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61^{o}

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Solution

The correct option is B $64^{o}$
The given angle is $183^{o} .$
One-third of the angle is $\frac{1}{3} \times 183^{o} = 61^{o}$

The supplementary angle of $61^{o}$ is $180^{o} - 61^{o} = 119^{o}$

Let the required angle is $x .$
$∴ 183^{o} - x = 119^{o}$
$\Rightarrow x = 183^{o} - 119^{o} = 64^{o}$

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What measure of angle must be subtracted from 183o to make it a supplementary angle of one-third of the given angle?

The correct option is B 64oThe given angle is 183o. One-third of the angle is 13×183o=61o The supplementary angle of 61o is 180o−61o=119o Let the required angle is x. ∴183o−x=119o ⇒x=183o−119o=64o

What measure of angle must be subtracted from $183^{o}$ to make it a supplementary angle of one-third of the given angle?