What molar ratio of Sn and Cl $_{2}$ is required to form a product mixture of SnCl $_{2}$ and SnCl $_{4}$ in 1 : 2 molar ratio?

3 : 5

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1 : 2

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2 : 3

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1 : 1

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Solution

The correct option is A 3 : 5
According to question, balanced reaction should be,

$3 S n + 5 C l_{2} \to S n C l_{2} + 2 S n C l_{4}$

So, according to balance reaction mole ratio of $S n$ and $C l_{2}$ is $3 : 5$ .

Hence, option A is correct.

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Similar questions

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$A + 2 N H_{4} C l \to B$

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What molar ratio of Sn and Cl2 is required to form a product mixture of SnCl2 and SnCl4 in 1 : 2 molar ratio?

The correct option is A 3 : 5According to question, balanced reaction should be,3Sn+5Cl2→SnCl2+2SnCl4So, according to balance reaction mole ratio of Sn and Cl2 is 3:5.Hence, option A is correct.

What molar ratio of Sn and Cl $_{2}$ is required to form a product mixture of SnCl $_{2}$ and SnCl $_{4}$ in 1 : 2 molar ratio?

The correct option is A 3 : 5
According to question, balanced reaction should be,

$3 S n + 5 C l_{2} \to S n C l_{2} + 2 S n C l_{4}$

So, according to balance reaction mole ratio of $S n$ and $C l_{2}$ is $3 : 5$ .

Hence, option A is correct.