What must be added to 1−x+x2–2x3 to get x3?
x3−x2+x−1
−1+x+x2−3x3
3x3−x2+x−1
None of these
The correct option is B: 3x3−x2+x−1
Let the term to be added be y.
⇒(1–x+x2–2x3)+y=x3
⇒y=x3–(1–x+x2–2x3)
⇒ y=x3–1+x–x2+2x3
∴ y=3x3–x2+x–1
so, 3x3–x2+x–1 must be added to (1−x+x2–2x3) to get x3.
What must be added to(x3+3x−8) to get (3x3+x2+6)?
What must be added to x2+3x−8 to get x2+x+6?