What must be added to 3x3+x2−22x+9 so that the result is exactly divisible by 3x2+7x−6 ?
Open in App
Solution
To find what should be added to 3x3+x2−22x+9 so that result is exactly divisible by 3x2+7x−6 therefore, 2x-3 should be added to 3x3+x2−22x+9 is divisible by 3x2+7x−6.