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Question

What must be added to 3x3+x222x+9 so that the result is exactly divisible by 3x2+7x6 ?

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Solution

To find what should be added to 3x3+x222x+9 so that result is exactly divisible by 3x2+7x6

therefore, 2x-3 should be added to 3x3+x222x+9 is divisible by 3x2+7x6.

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