What must be added to 4 x 2-8 x- to make it a perfect square-A- 4B- 8C- 16D- 2

The correct option is A 4We know that, 4x^2+8x=(2x)^2+2×(2x)×2 Adding 4 on both sides gives, 4x^2+8x+4=(2x)^2+2×(2x)×2+4 Since, 4x^2+8x+4=(2x+2)^2 4 is to be a ...

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Standard IX

Mathematics

Algebraic Identities

What must be ...

Question

What must be added to $4 x^{2} + 8 x$ , to make it a perfect square?

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Solution

The correct option is A 4
We know that, $4 x^{2} + 8 x = (2 x)^{2} + 2 \times (2 x) \times 2$
Adding 4 on both sides gives,
$4 x^{2} + 8 x + 4 = (2 x)^{2} + 2 \times (2 x) \times 2 + 4$
Since, $4 x^{2} + 8 x + 4 = (2 x + 2)^{2}$
4 is to be added to $4 x^{2} + 8 x$ to make it a perfect square.

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What must be added to 4x2+8x, to make it a perfect square?

The correct option is A 4We know that, 4x2+8x=(2x)2+2×(2x)×2 Adding 4 on both sides gives, 4x2+8x+4=(2x)2+2×(2x)×2+4 Since, 4x2+8x+4=(2x+2)2 4 is to be added to 4x2+8x to make it a perfect square.

What must be added to $4 x^{2} + 8 x$ , to make it a perfect square?

The correct option is A 4
We know that, $4 x^{2} + 8 x = (2 x)^{2} + 2 \times (2 x) \times 2$
Adding 4 on both sides gives,
$4 x^{2} + 8 x + 4 = (2 x)^{2} + 2 \times (2 x) \times 2 + 4$
Since, $4 x^{2} + 8 x + 4 = (2 x + 2)^{2}$
4 is to be added to $4 x^{2} + 8 x$ to make it a perfect square.