What must be added to f(x)=4x4+2x3+2x2+x−1 so that the resulting polynomial is divisible by g(x)=x2+2x−3
A
−61x+65
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B
2x−15
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C
−15x+2
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D
None of these
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Solution
The correct option is B None of these x2+2x−3)¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯4x4+2x3+2x2+x−1(4x2−6x+26 4−x4+−8x3−+12x2–––––––––––––––––– −6x3+14x2+x−1 −+6x3−+12x2+−18x–––––––––––––––––––– 26x2−17x−1 +−26x2+−52x−+78––––––––––––––––––– −69x+77 We have to add 69x−77 so that 4x4+2x3+2x2+x−1 is completely divisible by x2+2x−3.