What must be added to (12+13−15) so that we get 3?
Given , the sum of the rational numbers is 3. Let the number to be added be x . (12+13−15)+x=3 ⇒1930+x=3 ⇒1930+x=3 x=3−1930 The required number is 7130 .
What must be added to 1−x+x2–2x3 to get x3?
What should be added to (12+13+15) to get 3?