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Question

What must be added to (x3+3x8) to get (3x3+x2+6)?


A

2x3+x23x+17

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B

2x3+x23x+14

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C

2x3+x2x+14

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D

2x3+4x23x+14

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Solution

The correct option is B

2x3+x23x+14


Let the expression to be added be y.

(x3+3x8)+y=3x3+x2+6y=(3x3+x2+6)(x3+3x8)

3x3+x2 +6
x3 +3x8
+–––––––––––––––
2x3+x23x+14

So we have to add (2x3+x23x+14) to(x3+3x8), to get the expression(3x3+x2+6).


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