What must be added to (x3+3x−8) to get (3x3+x2+6)?
2x3+x2−3x+14
Let the expression to be added be y.
(x3+3x−8)+y=3x3+x2+6⇒y=(3x3+x2+6)−(x3+3x−8)
3x3+x2 +6
x3 +3x−8
− − +–––––––––––––––––
2x3+x2−3x+14
So we have to add (2x3+x2−3x+14) to(x3+3x−8), to get the expression(3x3+x2+6).