What must be subtracted from $14 x^{2} + 13 x - 15$ so that the resulting polynomial is exactly divisible by $7 x - 4$ .

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Solution

We divide $14 x^{2} + 13 x - 15$ by $7 x - 4$ as shown in the above image:

From the above division, we get that the quotient is $2 x + 3$ and the remainder is $- 3$

Hence, $3$ must be subtracted from . $14 x^{2} + 13 x - 15$ so that the resulting polynomial is exactly divisible by $7 x - 4$ .

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