What must be subtracted from $(4 x^{3} - 3 x + 5)$ to get $(2 x^{2} - 3 x^{3} + 5 x - 2)$ ?

$x^{3} - 2 x^{2} - 8 x + 7$

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$7 x^{3} + 2 x^{2} - 8 x + 7$

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$7 x^{3} - 2 x^{2} - 8 x + 3$

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$7 x^{3} - 2 x^{2} - 8 x + 7$

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Solution

The correct option is D
$7 x^{3} - 2 x^{2} - 8 x + 7$

Let's take the unknown expression to be $p (x)$ .
So, $(4 x^{3} - 3 x + 5) - p (x)$
$= (2 x^{2} - 3 x^{3} + 5 x - 2)$
$p (x) = (4 x^{3} - 3 x + 5)$
$- (2 x^{2} - 3 x^{3} + 5 x - 2)$

$4 x^{3} - 3 x + 5$
$- 3 x^{3} + 5 x - 2 + 2 x^{2}$
$(+) (-) (+) (-)$
________________________
$7 x^{3} - 8 x + 7 - 2 x^{2}$

$p (x) = 7 x^{3} - 2 x^{2} - 8 x + 7$

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Similar questions

4 x^{3} - 3 x + 5

2 x^{2} - 3 x^{3} + 5 x - 2

What must be subtracted from $4 x^{3} - 3 x + 5$ to get $2 x^{2} - 3 x^{3} + 5 x - 2$ ?

x^{4} + 4 x^{2} - 3 x + 7

3 x^{3} - x^{2} + 2 x + 1

x^{4} - 3 x^{3} + 5 x^{2} - 5 x + 6

(1 + x + 2 x^{2} - 3 x^{3})

(2 x^{2} - 4 x^{3} + 4 x + 9)

(- x^{3} + 3 x + 8)

\frac{4 x^{3} - 7 x^{2} + 5}{2 x - 1}

2 x^{2} - 5 x + 1

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