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Question

What must be subtracted from a2b+6a2b27ab+4to get 7a2b2+2a3b+6ab1

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Solution

Let x be the expression subtracted from a2b+6a2b27ab+4 to get 7a2b2+2a3b+6ab1

a2b+6a2b27ab+4x=7a2b2+2a3b+6ab1

x=7a2b2+2a3b+6ab1(a2b+6a2b27ab+4)

x=7a2b2+2a3b+6ab1a2b6a2b2+7ab4

x=13a2b2+2a3ba2b+13ab5

x=13a2b22a3b+a2b13ab+5

,13a2b22a3b+a2b13ab+5 must be subtracted.

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