What must be subtracted from or added to 6x4+7x3-26x2-25x+25 so that it may be exactly divisible by 3x2-x+4?
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Solution
When 6x^4+7x^3+26x^2-25x+25 is divided by 3x^2-x+4 , we get quotient 2x^2+3x +7 and remainder (-30x -3). For 0 remainder , we have to subtract (-30x -3) from 6x^4+7x^3+26x^2-25x+25 i.e 6x^4+7x^3+26x^2 + 5x+28