What must your speed be to stop just before the hole?

18 m s^{- 1}

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17.8 m s^{- 1}

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17.3 m s^{- 1}

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16.9 m s^{- 1}

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Solution

The correct option is B $17.8 m s^{- 1}$
When the body will move the friction should be kinetic. From FBD,
$m a = m g sin 20 - f = m g sin 20 - μ_{k} m g cos 20$
or, $a = 10 (0.3420 - 0.7 \times 0.9507) = - 3.2 m / s^{2}$
by using , $v^{2} - u^{2} = 2 a S$ ,
here, $0 - u^{2} = - 2 \times 3.2 \times 50$
$u = \sqrt{320} = 17.8 m / s$ .

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What must your speed be to stop just before the hole?

The correct option is B 17.8ms−1When the body will move the friction should be kinetic. From FBD,ma=mgsin20−f=mgsin20−μkmgcos20or, a=10(0.3420−0.7×0.9507)=−3.2m/s2by using , v2−u2=2aS,here,0−u2=−2×3.2×50u=√320=17.8m/s .