Question

What number should be added to $\frac{-5}{8}$ so as to get $\frac{-3}{2}$?

Answer 1

Let the required number be x.

Now,

$\frac{-5}{8}+x=\frac{-3}{2}$

$\Rightarrow \frac{-5}{8}+x+\frac{5}{8}=\frac{-3}{2}+\frac{5}{8}$ (Adding $\frac{5}{8}$ to both the sides)

$$\begin{gathered} \Rightarrow x=\left({\displaystyle \frac{-3}{2}}+{\displaystyle \frac{5}{8}}\right) \\ \Rightarrow x=\left({\displaystyle \frac{-12}{8}}+{\displaystyle \frac{5}{8}}\right) \\ \Rightarrow x=\left(\frac{-12+5}{8}\right) \\ \Rightarrow x=\frac{-7}{8} \end{gathered}$$

Hence, the required number is $\frac{-7}{8}$.