Question

What number should be added to $(\frac{2}{3}+\frac{3}{5})$ to get $\frac{-2}{15}$?

Answer 1

Let the required number be $x$

According to the equestion,

$(\frac{2}{3}+\frac{3}{5})+x=\frac{-2}{15}$

$\Rightarrow x=\frac{-2}{15}-(\frac{2}{3}+\frac{3}{5})$

$=\frac{-2}{15}-(\frac{2\times 5}{3\times 5}+\frac{3\times 3}{5\times 3})$

$=\frac{-2}{15}-(\frac{10}{15}+\frac{9}{15})$

$=\frac{-2}{15}-\left(\frac{10+9}{15}\right)$

$=\frac{-2-19}{15}$

$=\frac{-21}{15}$

$=\frac{-7}{5}$

Hence, the required number is $\frac{-7}{5}$.