Question

What of the following contain largest number of carbon atoms?

• A. 15 gm ethane, $C_6{H}_6\left(B\right)$
• B. 40.2 gm sodium oxalate, $N{a}_2{C}_2{O}_4$
• C. 72 gm glucose, $C_6{H}_{12}{O}_6$
• D. 35 gm pentene, $C_5{H}_{10}$

Answer 1

The correct option is C 72 gm glucose, $C_6{H}_{12}{O}_6$

(A) $15$ gram of ethane $\left(C_2{H}_6\right)$
Has number of moles $=\frac{t_5}{30}=0.2$ moles
Has number of carbon atoms $=2\times 0.2\times 6\times {10}^{23}$
$=2.4\times {10}^{23}$ C-atom
(B) $402$ gram of $N{a}_2{C}_2{O}_4$
Has number of moles $=\frac{40.2}{134}=0.3$ moles
and number of C-atoms $=0.3\times 6\times {10}^{23}\times 2$
$=3.6\times {10}^{23}$ C-atoms
(C) $72$ gram of glucose have numbers of moles $=\frac{72}{180}=0.4$ moles
Now numbers of C-atoms $\Rightarrow 0.4\times 6\times 6\times {10}^{23}$
$=144\times {10}^{23}$ C-atoms
(D) $35$ gram of $C_5{H}_{10}$ has number of moles $=\frac{35}{70}=0.2$
Number of C-atoms$=0.2\times 5\times 6\times {10}^{23}$
$=6\times {10}^{23}$ atoms
Hence Option (C) 72 gram of glucose has maximum C-atoms.