What percent is:
$27 c m$ of $1.80 m$

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Solution

We have to find percentage of $27 c m$ of $1.80 m$
So, we have to find how much percent is $27 c m$ out of $180 c m$ [ $1 m = 100 c m$ ]
i.e., $\frac{27}{180} \times 100 =$ $15 %$
Hence, percent of $27 c m$ out of $1.80 m$ is $15 %$ .

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