What percent of $70$ kg is $2.1$ kg?

5 %

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2.1 %

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3 %

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6 %

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Solution

The correct option is C $3 %$
Required percent $= \frac{2.1 k g}{70 k g} \times 100$

Suggest Corrections

Similar questions

270

108

2.1

2.1 \times 10^{9} N / m^{2}

m = 32.96 k g

16 m^{3}

1.8 g {c m}^{- 3}

6.3 \times 10^{3} k g m^{- 3}

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