What percent of length of a wire will increase by applying a stress of $1 k g$ . wt/mm $^{2}$ on it.
[Y $=$ 1x10 $^{11}$ Nm $^{- 2}$ and $1 k g w t$ $=$ 9.8N]

0.0078

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0.0088

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0.0098

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0.0067

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Solution

The correct option is C $0.0098$ %
$Y = \frac{S t r e s s}{S t r a i n}$
$S t r a i n = \frac{S t r e s s}{Y}$
$= \frac{9.8 \times 10^{6}}{1 \times 10^{11}}$
$= 9.8 \times 10^{- 3}$ %
$= 0.0098$ %
So, change in length is $0.0098$ %

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What percent of length of a wire will increase by applying a stress of 1kg. wt/mm2 on it. [Y=1x1011Nm−2 and 1kgwt = 9.8N]

The correct option is C 0.0098%Y=StressStrainStrain=StressY=9.8×1061×1011=9.8×10−3 %=0.0098 %So, change in length is 0.0098%

What percent of length of a wire will increase by applying a stress of $1 k g$ . wt/mm $^{2}$ on it.
[Y $=$ 1x10 $^{11}$ Nm $^{- 2}$ and $1 k g w t$ $=$ 9.8N]

The correct option is C $0.0098$ %
$Y = \frac{S t r e s s}{S t r a i n}$
$S t r a i n = \frac{S t r e s s}{Y}$
$= \frac{9.8 \times 10^{6}}{1 \times 10^{11}}$
$= 9.8 \times 10^{- 3}$ %
$= 0.0098$ %
So, change in length is $0.0098$ %