Question

What percentage of a sample of nitrogen must be allowed to escape if its temperature, pressure and volume are changed from ${220}^{\circ }C,3.0atm$ and $1.65L$ to ${110}^{\circ }C,0.7atm$ and $1.0L$ respectively?

Answer 1

$m$ (mass of the gas) $=\frac{PV\times M}{RT}\left(TinKelvin\right)$
Mass of gas before escaping $=\frac{3.0\times 1.65\times 28}{0.0821\times 493}=3.42g$
Mass of gas after escaping $=\frac{0.7\times 1.0\times 28}{0.0821\times 383}=0.62g$
Percentage of nitrogen allowed to escape
$=\frac{(3.42-0.62)}{3.42}\times 100=81.87$