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Basic Buffer Action

What percenta...

Question

What percentage of carbon in the $H_{2} C O_{3}, H C O_{3}^{-}$ buffer should be in the form of $H C O_{3}^{-}$ so as to have a neutral solution ? $(K_{a} = 4 \times 10^{- 7})$

20 %

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40 %

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60 %

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80 %

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Solution

The correct option is D $80 %$
$p H = p K_{a} + log \frac{H C O_{3}^{-}}{H_{2} C O_{3}}$
$7 = 7 - log + log \frac{H C O_{3}^{-}}{H_{2} C O_{3}} \frac{H C O_{3}^{-}}{(H_{2} C O_{3})} = 4$
% $H C O_{3}^{-} = \frac{4}{5} \times 100 \Rightarrow 80$ %

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