The correct option is
C 20%for a square to end with'1' it's root should have
either '1' or '1' as ones digit.
i.e. 12=1 92=81 112=121
∴ no. of squares that end with 1 before 702⇒
n(12,92,112,192,212,292,312,392,412,492,512,592,612,692)
[10 of squares that and with '1' before 103] = 14
Percentage = [no.ofsquaresnumber1−70thathavesquaresthatandwith1]70×100
=1470×100
percentage = 20%
∴ 20 % of number from 1-70 have squares that
and with digit '1'.