What percentage of tetrahedral holes is occupied in diamond?

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Solution

The correct option is B 50
$50 %$ of the tetrahedral holes is occupied in diamond. The structure is given above.

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Similar questions

Compute the percentage void space per unit volume of unit cell in zinc-fluride structure. In zinc fluoride, anions occupy

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Q. In zinc blende, the percentage of tetrahedral voids occupied by

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ions is:

Q. Spinel is an important class of oxides consisting of two types of metal ions with the oxide ions arranged in CCP pattern. The normal spinel has 1/8 of the tetrahedral holes occupied by one type of metal ion and 1/2 of the octahedral holes occupied by another type of metal ion. Such a spine is formed by

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In a normal spinel type structure, the oxide ions are arranged in ccp whereas $\frac{1}{8}$ tetrahedral holes are occupied by $Z n^{2 +}$ ions and 50% of octahedral holes are occupied by $F e^{3 +}$ ions. The formula of the compound is ?

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What percentage of tetrahedral holes is occupied in diamond?

The correct option is B 5050% of the tetrahedral holes is occupied in diamond. The structure is given above.

The correct option is B 50
$50 %$ of the tetrahedral holes is occupied in diamond. The structure is given above.