What possibly can be the ratio of the de Broglie wavelength of two electrons having the same initial energy and accelerated through 50V and 200V
A
3:5
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B
10:3
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C
6:2
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D
2:1
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Solution
The correct option is D2:1 We know that,
de broglie wavelength, λ=1√2meV
Where, V=potential m=mass of electron
So, λ∝1√V
Given that electrons are accelerated through 50V and 200V respectively, therefore, λ1λ2=√V2√V1=√200√50=2:1