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Cross Aldol Condensation

What product ...

Question

What product would be formed from a $S_{N} 2$ reaction between (R)-2-bromobutane and hydroxide ions?

A

2-butanol

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B

(S)-2-butanol

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C

(R)-3-hexanol

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D

3-pentanol

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Solution

The correct option is B (S)-2-butanol
$S_{N} 2$ reaction occurs with the inversion of configuration known as Walden inversion and no intermediate is formed in this reaction.

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Similar questions

Q. What product would be formed from the

S_{N} 2

reaction of (R)-2-bromobutane and hydroxide ion?

Q. Reaction of R-2-bromobutane with aqueous KOH follows two parallel reactions, one by

S_{N} 2

(complete inversion) and other by

S_{N} 1

(complete racemization). Specific optical activity for R-2-butanol is

- {13.50}^{\circ} / g m L

per dm length of the polarimeter.

If in a 10 cm tube polarimeter, 10 ml of R-2-bromobutane along with KOH is filled, then after complete reaction of R-2-bromobutane, the mass of all alcohols formed is found equal to 5 g of which 1 g is of R-2-butanol. Then, the total optical rotation (in degree) of the solution is

Q. Reaction of R-2-bromobutane with aqueous KOH follows two parallel reactions, one by

S_{N} 2

(complete inversion) and other by

S_{N} 1

(complete racemization). Specific optical activity for R-2-butanol is

- {13.50}^{\circ} / g m L

per dm length of the polarimeter.

If in a 10 cm tube polarimeter, 10 ml of R-2-bromobutane along with KOH is filled, then after complete reaction of R-2-bromobutane, the mass of all alcohols formed is found equal to 5 g of which 1 g is of R-2-butanol. Then, the total optical rotation (in degree) of the solution is

Q. What product would be formed from the reaction of (R)-2-bromooctane and hydroxide ion in dimethylformamide (DMF) at room temperature?
(correct answer +1, wrong answer -0.25)

(R)-2-Bromobutane is allowed to react with $N a I$ in acetone. The product formed is :

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