What proportion of the offsprings obtained from cross AABBCC×AaBbCc will be completely heterozygous for all the genes segregated independently?
A
1/8
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B
1/4
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C
1/2
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D
1/16
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Solution
The correct option is A1/8 Since one parent is homozygous AABBCC the genotype formed will be only 1 type i.e. ABC. The other parent is heterozygous for all genes. About 1/8th or 12.5% of total offspring will be heterozygous at all three-locus.