What proportion of the offsprings obtained from cross AABBCC - AaBbCc will be completely heterozygous for all the genes segregated independently-

The correct option is A 1/8 Since one parent is homozygous #160;AABBCC #160; the genotype formed will be only 1 type i.e. ABC. The other parent is het ...

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Standard XII

Biology

Rediscovery of Mendelism

What proporti...

Question

What proportion of the offsprings obtained from cross $A A B B C C \times A a B b C c$ will be completely heterozygous for all the genes segregated independently?

1 / 8

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Solution

The correct option is A $1 / 8$
Since one parent is homozygous AABBCC the genotype formed will be only 1 type i.e. ABC. The other parent is heterozygous for all genes. About 1/8th or 12.5% of total offspring will be heterozygous at all three-locus.

So the answer is '1/8'.

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What proportion of the offsprings obtained from cross AABBCC×AaBbCc will be completely heterozygous for all the genes segregated independently?

The correct option is A 1/8Since one parent is homozygous AABBCC the genotype formed will be only 1 type i.e. ABC. The other parent is heterozygous for all genes. About 1/8th or 12.5% of total offspring will be heterozygous at all three-locus.So the answer is '1/8'.

What proportion of the offsprings obtained from cross $A A B B C C \times A a B b C c$ will be completely heterozygous for all the genes segregated independently?

The correct option is A $1 / 8$
Since one parent is homozygous AABBCC the genotype formed will be only 1 type i.e. ABC. The other parent is heterozygous for all genes. About 1/8th or 12.5% of total offspring will be heterozygous at all three-locus.

So the answer is '1/8'.