Question

What quantity must be added to each term of the ratio $8:15$ so that it becomes equal to $3:5$?

• A. $1\frac{1}{4}$
• B. $2$
• C. $2\frac{1}{2}$
• D. $3$

Answer 1

The correct option is C $2\frac{1}{2}$

Let $x$ be added to each term of the ratio $8:15$.
Given: $\frac{(8+x)}{(15+x)}=\frac{3}{5}$
$\Rightarrow 40+5x=45+3x$
$\Rightarrow x=2\frac{1}{2}$