What quantity of ammonium sulphate is necessary for the production of ammonia gas sufficient to neutralize a solution containing $292 g$ of $H C l$ ?

[ $H C l = 36.5, (N H_{4})_{2} S O_{4} = 132, N H_{3} = 17$ ]

272 g

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408 g

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528 g

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1056 g

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Solution

The correct option is B $528 g$
Eq. of $(N H_{4})_{2} S O_{4} =$ Eq. of $H C l$ .

Let, the amount of $(N H_{4})_{2} S O_{4}$ needed is $x$ g.

Then, $\frac{x}{132 / 2} = \frac{292}{36.5}$ .

Hence, $x = 528$ g.

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