Question

What quantity of copper (II) oxide will react with 2.80 litre of hydrogen at NTP ?

Answer 1

The quantity of copper (II) oxide will react with 2.80 litre of hydrogen at NTP will be as:

The balanced equation is:
$\underset{79.5g}{\underset{1mol}{CuO}}+\underset{22.4litreatNTP}{\underset{mol}{H_2}}\to Cu+H_{2}O$
22.4 litre of hydrogen at NTP reduce $CuO=79.5g$
2.80 litre of hydrogen at NTP will reduce $CuO$ $=\frac{79.5}{22.4}\times 2.80g=9.95g$