What quantity of heat would be given out by 200 gm of copper in cooling from 80 -C to 20 -C Specific heat of copper - 0-09 cal g -1 - C -1-

The correct option is A 1080 cal Given , #160; m=200g , #160;θ_1=80^0C , θ_2=20^0C We have , specific heat of copper c=0.09cal/g ^oC Now , ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Physics

Specific Heat Capacity

What quantity...

Question

What quantity of heat would be given out by $200 g m$ of copper in cooling from $80^{\circ} C$ to $20^{\circ} C$ (Specific heat of copper = 0.09 ${c a l g}^{- 1}$ $^{\circ} C^{- 1}$ )?

1080 c a l

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1000 c a l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1500 c a l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1100 c a l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $1080 c a l$
Given , $m = 200 g, θ_{1} = 80^{0} C, θ_{2} = 20^{0} C$
We have , specific heat of copper $c = 0.09 c a l / g -^{o} C$
Now , heat lost by copper is given by the definition of specific heat c ,
$Q = m c Δ θ = m c (θ_{1} - θ_{2})$
or $Q = 200 \times 0.09 \times (80 - 20) = 1080 c a l$

Suggest Corrections

Similar questions

$50 g$ of copper is heated to increase its temperature by $10^{\circ} C$ . If the same quantity of heat is given to $10 g$ of water, then what would be the rise in its temperature?
(specific heat of copper $= 420 J / k g /^{\circ} C$ , specific heat of water $= 4200 J / k g /^{\circ} C$ )

Q. Find the heat lost by a copper cube of mass

400 g

when it cools from

100^{\circ} C

30^{\circ} C

. (Specific of heat of copper

= 390 J

{k g}^{- 1}

^{\circ} C^{- 1}

200 g

of copper at

200^{o} C

is cooled to

20^{o} C

. If the specific heat capacity of copper is

0.4 J / g^{o} C

, calculate the heat energy given out(

i n J

)

$50 g$ of copper is heated to increase its temperature by $10^{\circ} C .$ If the same quantity of heat is given to $10 g$ of water, the rise in its temperature is:

(Given: ${Specific heat of copper = 420 Joule kg}^{- 1}^{\circ} C^{- 1}$ , ${Specific heat of water = 4200 Joule kg}^{- 1}^{\circ} C^{- 1}$ )

Q. The water equivalent of a copper calorimeter is

4.5 g

. If the specific heat of copper is

0.09 cal g^{- 1} C^{- 1}

, then

Join BYJU'S Learning Program

What quantity of heat would be given out by 200gm of copper in cooling from 80∘C to 20∘C (Specific heat of copper = 0.09 calg−1∘C−1)?

The correct option is A 1080calGiven , m=200g,θ1=800C,θ2=200CWe have , specific heat of copper c=0.09cal/g−oCNow , heat lost by copper is given by the definition of specific heat c , Q=mcΔθ=mc(θ1−θ2)or Q=200×0.09×(80−20)=1080cal

What quantity of heat would be given out by $200 g m$ of copper in cooling from $80^{\circ} C$ to $20^{\circ} C$ (Specific heat of copper = 0.09 ${c a l g}^{- 1}$ $^{\circ} C^{- 1}$ )?