Question

What rational number should be added to $-\frac{3}{16}$ to get $\frac{11}{24}?$

Answer 1

Step : Finding the other number
Let, the required number be $x$.
According to question x should be added to $-\frac{3}{16}$
to get $\frac{11}{24}$ .
$\therefore x+\left(\frac{-3}{16}\right)=\frac{11}{24}$
$\Rightarrow x-\frac{3}{16}=\frac{11}{24}$
$x=\frac{11}{24}+\frac{3}{16}$
$=\frac{11\times 2}{24\times 2}+\frac{3\times 3}{16\times 3}[\because \text{LCM of}24,16=48]$
$=\frac{22}{48}+\frac{9}{48}=\frac{22+9}{48}=\frac{31}{48}$

Hence, $\frac{31}{48}$ should be added to $-\frac{3}{16}$ to get $\frac{11}{24}$ .