What resistance must be connected to a 15 Ω resistance to provide an effective resistance of 6 Ω?
10 Ω
Given resistance, R1=15 Ω
Effective resistance, R=6 Ω
Let the resistance to be connected be R2.
In a parallel combination of resistors, the equivalent resistance is less than the individual resistors in the circuit.
Since effective resistance is less than R1, so R2 must be connected in parallel with R1.
In parallel combination, effective resistance,
1R=1R1+1R2
⇒16Ω=115Ω+1R2
⇒1R2=16Ω−115Ω
⇒1R2=15−615×6 Ω
⇒R2=90 Ω9
Hence, R2=10 Ω