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Raoult's Law

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Question

What's the molarity and molality of a $13 %$ solution by weight of sulphuric acid with the density of 1.02g/ml?

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Solution

Density = 1.02 g/mL
Let's assume 1000ml or 1litre of solution
Therefore weight of solution $= (\frac{1.02}{1}) \times 1000$
$= 1020 g$

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