Question

What should be added to $\frac{-12}{5}$ to get 3?

Answer 1

Let the number that is to be added be x.

$\begin{array}{l}\frac{\begin{array}{l}\\ -12\end{array}}{5}+x=3\\ =>x=3-\frac{(-12)}{5}\\ =>x=\frac{15+12}{5}\\ =>x=\frac{27}{5}\\ \text{Hence, the required number is}\frac{27}{5}\text{.}\\ \end{array}$