Question

What should be added to $\left(\frac{2}{3}+\frac{3}{5}\right)$ to get $\frac{-2}{15}?$

Answer 1

$$\begin{gathered} \mathrm{Let}x\mathrm{be}\mathrm{added}. \\ \therefore x+(\frac{2}{3}+\frac{3}{5})=\frac{-2}{15} \\ \Rightarrow x+(\frac{10}{15}+\frac{9}{15})=\frac{-2}{15} \\ \Rightarrow x+\left(\frac{10+9}{15}\right)=\frac{-2}{15} \\ \Rightarrow x=\frac{-2}{15}-\frac{19}{15} \\ \Rightarrow x=\frac{-2-19}{15} \\ \Rightarrow x=\frac{-21}{15} \\ \Rightarrow x=\frac{-7}{5} \end{gathered}$$