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Question

What should be added to 3xy4a2+5b2+2 to get 5+4a2+2b27xy?

A
8a2+3b211xy+10
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B
8a2+3b2+10xy+7
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C
8a23b2+10xy+7
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D
8a2+3b2+10xy+7
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Solution

The correct option is B 8a2+3b2+10xy+7
Let the term to be added be 's' .
3xy4a2+5b2+2+s=5+4a2+2b27xy
s=(5+4a2+2b27xy)(3xy4a2+5b2+2)
Rearranging the terms and subtracting,
4a2+5b2+3xy+2
4a2+2b27xy5
(-) (-) (+) (+)
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8a2+3b2+10xy+7

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