Question

What should be added to $9\frac{2}{3}$ to get 19?

Answer 1

Let x be added to $9\frac{2}{3}$ to get 19.

$$\begin{gathered} \therefore 9\frac{2}{3}+\mathrm{x}=19 \\ \mathrm{Thus},\mathrm{we}\mathrm{have}: \\ \mathrm{x}=19-9\frac{2}{3} \\ =\frac{19}{1}-\frac{29}{3}\mathrm{L}.\mathrm{C}.\mathrm{M}.\mathrm{of}1\mathrm{and}3\mathrm{is}3. \\ =\frac{\left(57-29\right)}{3}\left\{\left[3÷1=3,3\times 19=57\right]\mathrm{and}\left[3÷3=1,1\times 29=29\right]\right\} \\ =\frac{28}{3}=9\frac{1}{3} \end{gathered}$$923