Question

What should be added to $\frac{-7}{12}$ to get $\frac{3}{8}$ ?

Answer 1

Step 1: Finding equations by using given conditions

Let, the required number be x.

Given, one of the other number $=\frac{-7}{12}$ and sum of two numbers $=\frac{3}{8}$.

According to the question,

$x+\left(\frac{-7}{12}\right)=\frac{3}{8}$

$\Rightarrow x-\frac{7}{12}=\frac{3}{8}----------\left(i\right)$

Step 2: Solving equation to get required number

$x=\frac{3}{8}+\frac{7}{12}$

$x=\frac{3\times 3}{8\times 3}+\frac{7\times 2}{12\times 2}$

$[\because LCMof8and12is24]$

$=\frac{9}{24}+\frac{14}{24}=\frac{9+14}{24}=\frac{23}{24}$

Hence, $\frac{23}{24}$ should be added to $\frac{-7}{12}$ to get $\frac{3}{8}$.